Decimal to hex

[sshika 3]

Hello

 

I realizes a program to convert decimal in hexa.

local function hexa(dec)
local B,K,OUT,I,D = 16,"0123456789ABCDEF","",0
  if dec == 0 then
    OUT = "00"
  elseif dec > 0 and dec < 16 then
    D = dec + 1
    OUT = "0"..string.sub(K,D,D)
  elseif dec > 16 and dec < 256 then
    V1 = math.modf(dec/B)+1
    V2 = (dec-V1*16)
    OUT = string.sub(K,V1,V1)..string.sub(K,V2,V2)
  end
  return OUT
end

this program convert a lower number in 256, and i use this in a formule

local function rod(x,y,n)
  lvl = br.getControlRodLevel(n)
  rouge = math.floor((100-lvl)*255/100)
  vert = math.floor(lvl*255/100)
  color = "#"..hexa(rouge)..hexa(vert).."00"
  setColor(color,0x0000FF)
  gpu.set(x,y,"█"..string.format("%3s",lvl).."█")
  setColor(0x0, 0xFFFFFF)
end

if i print color, i obtain a value "#00FF00" to change color, but the format is not valid. There is a function to change format of this value ?

 

thank you.

[Magik6k 17]

The color value is just a integer, the way you obtain it is r*256*256 + g * 256 + b

[sshika 3]

ok thank you.

[dgelessus 26]

By the way, if you want to display a number as hexadecimal, it's much easier to use string.format:

("%x"):format(256) -- = "100"

But as said above, color values aren't strings, meaning that you don't need to convert them to any specfic number format. 0x100 and 256 are both of the type number and are equal.